Question 1095409
<br>With the given information that the number of loonies is 4 more than 3/7 the number of toonies, I would start my algebraic solution with...
let 7x = number of toonies
then 3x+4 = number of loonies<br>
Of course you could define your variables differently and work with fractions; but I prefer to make my work easier by avoiding fractions if possible.<br>
With that start, we know the number of quarters is 8 times the number of loonies and toonies together:
8(10x+4) = 80x+32 = number of quarters<br>
Now we have all the numbers in terms of a single variable.  So write and solve the equation that says the total value of the coins is $160:
{{{2(7x)+1(3x+4)+.25(80x+32) = 160}}}
{{{14x+3x+4+20x+8 = 160}}}
{{{37x = 148}}}
{{{x = 4}}}<br>
number of toonies: 7x = 28
number of loonies: 3x+4 = 16
number of quarters: 80x+32 = 352