Question 1095256
<br>For the method you were asked to use, the table might look like this:<br>
{{{matrix(3,4,qty,.60,.30,.50,number of liters,x,y,16,liters of alcohol,.60x,.30y,.50(16)=8)}}}<br>
Then your two equations (from rows 2 and 3 of the table) are for the total number of liters...
{{{x+y=16}}}
and for the total amount of alcohol...
{{{.60x + .30y = 8}}}<br>
While that is a good way to learn to solve this kind of problem, the method suggested by the other tutor (using only one variable) is, I think, easier.<br>
And for a much faster way to the answer, notice that the percentage of the final mixture, 50%, is "twice as close" to 60% as it is to 30%; that means you need to use twice as much of the 60% alcohol as the 30% alcohol.<br>
18 liters, using twice as much of the 60% alcohol, means 12 liters of the 60% and 6 liters of the 30%.