Question 1095225
Let the consecutive odd integers be:
{{{ n }}}, {{{ n+2 }}}, and {{{ n + 4 }}}
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{{{ n + 19 = 3*( n + 4 ) - 67 }}}
{{{ n + 19 = 3n + 12 - 67 }}}
{{{ 2n = 19 + 67 - 12 }}}
{{{ 2n = 74 }}}
{{{ n = 37 }}}
and
{{{ n+2 = 39 }}}
and
{{{ n + 4 = 41 }}}
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The numbers are 37, 39, and 41
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check:
{{{ n + 19 = 3*( n + 4) - 67 }}}
{{{ 37 + 19 = 3*41 - 67 }}}
{{{ 56 = 123 - 67 }}}
{{{ 56 = 56 }}}
OK