Question 1094979

If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC.

Picture of the equation: https://i.imgur.com/ou44uBB.png

I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave a poor example and didn't really try explaining it to me. What am I supposed to do with the fraction part of the equation to solve for angle HBC? 
<pre>You set &#8737;EBC = &#8737;EBH, but the 2 angles are not equal, so you CANNOT do that. And, as far as I see, none of the angles are equal.
Unless other info is given, &#8737;HBC will not have a NUMERICAL value.
&#8737;EBC = 31a – 2		&#8737;EBH = 4a + 45
&#8737;EBH + &#8737;HBC = &#8737;EBC
4a + 45 + &#8737;HBC = 31a - 2 -------- Substituting 4a + 45 for &#8737;EBH, and 31a – 2 for &#8737;EBC
&#8737;HBC  = 31a – 2 – 4a – 45
&#8737;HBC = {{{highlight_green(27a - 47)}}}