Question 1095022
At least 8 is 8, 9, 10
for 8: 10C8*0.97^8*0.03^2=0.0317
for 9: 10C9*0.97^9*0.03=0.2281
for 10, the largest, since the expected value is 9.7, 0.97^10=0.7374
The sum is 0.9972
Check by looking at 7, which must be almost all the rest 10C7*0.97^7+0.03^3=0.0026
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np=97, mean
variance is np(1-p)=2.91
sd is sqrt (V)=1.71
Note that n(1-p)=3 and typically that is too small to use the continuity correction factor
For at least 95, use 94.5
z>  (94.5-97)/1.71
z > -1.46
p=0.9279