Question 1094843
the numerator of a fraction is one less than its denominator .
<pre>
Denominator = D
Numerator = D-1
Original Fraction = {{{(D-1)/D}}}
</pre>
if three is added to each of the numerator & denominator, 
<pre>
New fraction = {{{(D-1+red(3))/(D+red(3))}}} or {{{(D+2)/(D+3)}}}
</pre>
the fraction is increased by 3/28. 
<pre>
So also, New fraction = Original fraction + {{{3/28}}} or {{{D/(D-1)+3/28}}} 

So we set the two expressions for the New fraction equal:

{{{(D+2)/(D+3)}}}{{{""=""}}}{{{(D-1)/D+3/28}}}

LCD = 28D(D+3)

{{{28D(D+2)}}}{{{""=""}}}{{{28(D+3)(D-1)+3D(D+3)}}}

Solve that and get D=4 and D=-7

Only the positive answer works.  Fraction = 3/4

Edwin</pre>