Question 1094680
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The area of your segment is {{{1/6}}} of the area of the circle with the radius 8 MINUS the area of the equilateral triangle with the side length 8, i.e.

the area of the segment = {{{(1/6)*pi*8^2}}} - {{{(8^2*sqrt(3))/4}}} = {{{(64pi)/6}}} - {{{(64*sqrt(3))/4}}} = {{{(32pi)/3}}} - {{{16*sqrt(3)}}} = 5.78 square inches (approximately).
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<U>Answer</U>.  &nbsp;The area of the segment is  &nbsp;&nbsp;{{{(32pi)/3}}} - {{{16*sqrt(3)}}} = 5.78 &nbsp;square inches &nbsp;(approximately).