Question 1094709
<pre>
x = smallest odd integer of the three 
x+2 = middle odd integer of the three
x+4 = largest odd integer of the three</pre>the sum of the largest and twice the smallest is 12 more than the middle number<pre>{{{matrix(1,9,
(matrix(2,1,the,largest)),
""+"",
2*(matrix(2,1,the,smallest)),
"",
""="",
"",
(matrix(3,1,the,middle,number)),
""+"",
12
)}}}

 (x+4)  + 2*(x) = (x+2) + 12
  x+4   + 2x    =  x+2  + 12
        3x + 4  =  x + 14
            2x  =  10
             x  =  5

 x = smallest odd integer of the three = 5 
x+2 = middle odd integer of the three = 5+2 = 7
x+4 = largest odd integer of the three = 5+4 = 9

We check the numbers in the words:</pre>3 consecutive odd integers<pre>5, 7, and 9 are all odd and consecutive. That checks.</pre>such that the sum of the largest and twice the smallest<pre>The largest is 9.  Twice the smallest is two time 5, or 10. 
Their sum, when we add those, 9+10 is 19 </pre>is 12 more than the middle number.<pre>Indeed! The middle number is 7, and 19 is 12 more than 7.
So we know we are right.

Edwin</pre>