Question 1094708
<font color="black" face="times" size="3">
The nth term of any geometric is
a(n) = a1*r^(n-1)


In our case, a1 = 3 and r = 2 so we have 
a(n) = 3*2^(n-1)


Now plug in n = 10
a(n) = 3*2^(n-1)
a(10) = 3*2^(10-1)
a(10) = 3*2^9
a(10) = 3*512
a(10) = <font color=red>1536</font>


The 10th term is <font color=red>1536</font>
</font>