Question 1094659
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{{{9x^2-24x+16=0}}}

{{{x=(24+- sqrt(24^2-4*9*16))/(2*9)}}}

*        {{{x=(24+- sqrt(576-576))/(2*9)}}}

{{{x=24/(2*9)}}}

{{{x=12/9}}}

{{{highlight(x=4/3)}}}


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Notice also that 9x^2 is a square term  and 16 is a square term, so you might be able to pick a factorization and check it.  Maybe this could work:
{{{(3x-4)(3x-4)}}}
F.O.I.L. Method,
{{{9x^2-12x-12x+16}}}
{{{9x^2-24x+16}}}
Same as the trinomial expression found earlier, so you would have
{{{(3x-4)^2=0}}}--------obviously {{{x=4/3}}}.






* <i>fixed sign mistake</i>