Question 1094651

find three consecutive odd intergers such that the second is 20 less than 3 times the third intergers

<pre>Let 1st integer be F
Then others are: F + 2, and F + 4
We then get: F + 2 = 3(F + 4) - 20
F + 2 = 3F + 12 - 20
F - 3F = - 8 - 2
- 2F = - 10
F, or 1st integer = {{{highlight_green(matrix(1,3, (- 10)/(- 2), "=", 5))}}}
2nd and 3rd integers: {{{highlight_green(matrix(1,3, "7,", and, 9))}}}