Question 97448
How many ounces of pure gold must be added to five ounces of something that is 1% gold in order that the mixture is 6% gold? 
x + 5(.01)= .06(x+5)
x + .05 = .06x + .30
x + .05 - .05 - .06x = .06x - .06x + .30 - .05
.94x = .25 
.94x/.94 = .25/.94
x= .27 ounces
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Correct  Nice job.
Cheers,
Stan H.