Question 97441
"At what elevation is the boiling point 99.5 degrees? "


{{{E(t) = 1000(100-t) + 580(100-t)^2}}} Start with the given function


{{{E(99.5)= 1000(100-99.5) + 580(100-99.5)^2}}} Plug in t=99.5



{{{E(99.5) = 1000(0.5) + 580(0.5)^2}}} Combine like terms



{{{E(99.5) = 1000(0.5) + 580(0.25)}}} Square 0.5 to get 0.25



{{{E(99.5) = 500 + 145}}} Multiply



{{{E(99.5) = 645}}} Add



So the elevation is 645 meters



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"At what elevation is the boiling point 100 degrees? "


{{{E(t) = 1000(100-100) + 580(100-100)^2}}} Start with the given function


{{{E(100)= 1000(100-100) + 580(100-100)^2}}} Plug in t=100



{{{E(100) = 1000(0) + 580(0)^2}}} Combine like terms



{{{E(100) = 1000(0) + 580(0)}}} Square 0 to get 0



{{{E(100) = 0 + 0}}} Multiply



{{{E(100) = 0}}} Add



So the elevation is 0 meters