Question 97437
{{{2/3+3y=5y-2/15}}} Start with the given equation



{{{(15)(2/3+3y)=(15)(5y-2/15)}}} Multiply both sides by the LCM of 15. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)



{{{10+45y=75y-2}}} Distribute and multiply 15 by each term on both sides



{{{45y=75y-2-10}}}Subtract 10 from both sides



{{{45y-75y=-2-10}}} Subtract 75y from both sides



{{{-30y=-2-10}}} Combine like terms on the left side



{{{-30y=-12}}} Combine like terms on the right side



{{{y=(-12)/(-30)}}} Divide both sides by -30 to isolate y




{{{y=2 / 5}}} Reduce


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Answer:

So our answer is {{{y=2 / 5}}}  (which is {{{y=0.4}}} in decimal form)