Question 1094336
<br>You choosing 3 of the 13 coins in the jar; the number of ways to do that is "13 choose 3":
{{{C(13,3) = 286}}}<br>
In order to get a total value of 36 cents, the three coins must be 1 quarter, 1 dime, and 1 penny.<br>
So you need to choose 1 of the 5 quarters ("5 choose 1" = 5 different ways), 1 of the 2 dimes ("2 choose 1" = 2 ways), and 1 of the 6 pennies ("6 choose 1" = 6 ways).<br>
So the total number of ways to get 1 of each coin is
{{{C(5,1)*C(2,1)*C(6,1) = 5*2*6 = 60}}}<br>
Then the probability of getting that desired outcome is the total number of way to get the desired outcome, divided by the total number of ways of picking 3 of the 13 coins:
{{{P = 60/286 = 30/143}}}