Question 1094209
<br>One part of the problem is determining how many different ways we can choose the 2 out of 7 times at bat that are the ones when he gets a hit.  That number of ways is the number "7 choose 2", which is
{{{(7*6)/(2*1) = 21}}}<br>
The other part is the probability part; each of the times that he gets a hit the probability is 0.2; each time he does not get a hit the probability is 0.8.<br>
All together, the probability that in his next 7 times at bat he gets  a hit 2 times and does not get a hit 5 times is
{{{21 * (0.2)^2 * (0.8)^5 = .27525}}} (approximately)