Question 1094162
Let your consecutive odd integers be n,n+2, and n+4. Then:
(n+2)(n+4)-5n=64
n²+6n+8-5n-64=0
n²+n-56=0
(n+8)(n-7)=0
n=7 or -8
Choosing the positive value for n, we get n=7,n+2=9, and n+4=11
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