Question 1094062
How many gallons of a fruit drink that is 50% real juice must be mixed with a fruit drink that is 20% real juice to obtain 12 gallons of a fruit drink that is 40% real juice?

I have attempted to make a chart as follows, but I'm not sure I have the numbers in the correct spots. Ignore the lines in between numbers, that's just to separate the different parts of the chart.

x  |   .50     | .50x
12   |    .40     |   .40(12)
x+12     |   .20    |   .20(x+12)
<pre>With x being the amount of 50% real juice, the amount of 20% real juice will be 12 - x, since the total in the final mixture is 12 gallons. We then get:
     x |  .50  |  .50x
12 - x |  .20  |  .20(12 - x)
  12   |  .40  |  .40(12)
Do you see now how it should be set up?
You then use the 3rd column: .5x + .2(12 - x) = .4(12) to solve.
Solve that for x, the amount of 50% real juice and you should get 8 gallons.