Question 1094064
<br>First a traditional solution using formal algebra....<br>
Let the distance (in km) be d.  Then the number of hours it took him to ride to the repair shop at 18 km/hr is d/18; the number of hours it took him to walk home at 6 km/hr is d/6.  Since the total time was 1 hour,<br>
{{{d/18 + d/6 = 1}}}
{{{d + 3d = 18}}}
{{{4d = 18}}}
{{{d = 4.5}}}<br>
The distance from his home to the repair shop was 4.5 km.<br>
And now for a solution that is made easier by first doing some logical analysis....<br>
His walking speed is 1/3 as fast as his riding speed.  Since he traveled the same distance riding and walking, he spent 3 times as much time walking as he did riding.  Since the total time was 1 hour, he rode for 1/4 hour and walked for 3/4 hour.  Then you can find the distance to the repair shop using either the riding part of the trip...
{{{18*(1/4) = 4.5}}}
or the walking part...
{{{6 * (3/4) = 4.5}}}