Question 1094041
{{{ h(t) = -16t^2 + 600t }}}
The formula for the t-coordinate of
the maximum {{{ h(t) }}} is:
{{{ t[max] = -b/(2a) }}}
{{{ a = -16 }}}
{{{ b = 600 }}}
{{{ t[max] = -600/(2*(-16) ) }}}
{{{ t[max] = 18.75 }}} sec
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Put this result back into equation
{{{ h(t) = -16*( 18.75 )^2 + 600*( 18.75 ) }}}
{{{ h(t) = -5625 + 11250 }}}
{{{ h( 18.75 ) = 5625 }}}
5,625 ft is the maximum height
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check the math