<PRE><B>Question 1094039</B>
How many gallons of a 80% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 70% antifreeze?
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Do it like this one:
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How many liters of a 75% antifreeze solution must be mixed with 50 liters of 30% antifreeze to get a mixture that is 65% antifreeze?
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Add L liters.
50*30 + L*75 = (50+L)*65
Solve for L
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