Question 1094027
Allison spent the same amount of time talking as on standby.  She used a total of one full cellphone battery charge.
This seems to be a constant rates situation.

<pre>

               RATE           TIME        COUNT OF BATTERY CHARGES

TALK            1/6             t         (1/6)t

STANDBY        1/210            t        (1/210)t

Total                                      1
</pre>


The total time length of the trip in HOURS was {{{highlight_green(2t)}}}.
Solve for t, in  {{{highlight_green(t/6+t/210=1)}}}.