Question 1093838
p=<3,5>;q=<2,4>
Find the angle between the vectors to the nearest tenth of a degree.
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p.q = |p|*|q|*cos(A)  --- dot product
p.q = 3*2 + 4*5 = 26
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|p| = sqrt(3^2 + 5^2) = sqrt(34)
|q| = sqrt(2^2 + 4^2) = 2sqrt(5)
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26 = 2sqrt(170)*cos(A)
cos(A) =~ 0.99705
A =~ 4.4 degs