Question 1093565
<br>Both earlier responses show the same correct answer, but the formal algebra is a lot of work.  I like methods of solving problems that get me to the answer with as little work as possible.  Here is what I would do with this problem.<br>
The distances covered in equal amounts of time with and against the current are in the ratio 100:80, or 5:4.  That means that must be the ratio of the speeds with and against the current.<br>
So if the speed of the current is c,
{{{(26+c)/(26-c) = 5/4}}}
{{{130-5c = 104+4c}}}
{{{26 = 9c}}}
{{{c = 26/9}}}