Question 1093787
Let {{{ w }}} = the width
{{{ 2w - 3 }}} = the length
Let {{{ P }}} = the perimeter
{{{ P = 2w + 2*( 2w - 3 ) }}}
{{{ 342 = 2w + 4w - 6 }}}
{{{ 6w = 348 }}}
{{{ w = 58 }}}
and
{{{ 2w - 3 = 113 }}}
The field is 58 x 113
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check:
{{{ P = 2*58 + 2*113 }}}
{{{ 342 = 116 + 226 }}}
{{{ 342 = 342 }}}
OK