Question 1093467
.
<pre>
Let the integer number N be the total number of problems assigned to each separately.


When George solved 22 problems,  (N-22) problems remained to solve.

When Dale solved 6 problems,  (N-6) problems remained to solve.


The condition says that

N-6 = 3*(N-22).


Simplify and solve:

N - 6 = 3N - 66,

66 - 6 = 3N - N,

2N = 60  ====>  N = {{{60/2}}} = 30.


<U>Answer</U>.  In all, 30 problems were assigned to each.


<U>Check</U>.   Please make check on your own.
</pre>


Nice problem !