Question 1093644
I'll make the substitution {{{ x = 60000 }}}
In 2015, he made:
{{{ x + .12x = 1.12x }}}
In 2016, he made:
{{{ 1.12x - .12*( 1.12x ) }}}
{{{ 1.12x - .1344x = .9856x }}}
and
{{{ .9856*60000 = 59136 }}}
$59,136