Question 1093595
The volume of a sphere of radius {{{r}}} is {{{(4/3)*pi*r^2}}} .
The volume of a cone with radius {{{r}}} and height {{{h}}} is
{{{(1/3)*pi*r^2*h}}} .
If sphere and cone with same radius have the same volume,
{{{(4/3)*pi*r^3=(1/3)*pi*r^2*h}}} .
That equation simplifies to
{{{4r=h}}}} <--> {{{h=2*diameter}}} .
So the cone height needs to be twice the diameter.
That is {{{highlight("200%")}}} of the diameter.