Question 1093498
Newton’s universal law of gravitation states that every object in the Universe
 attracts every other object with a force, F, that is directly proportional to the
 product of their masses, 1 m and 2 m , and inversely proportional to the square of
 the distance, d, that separates them. If the two objects each lose half of their
 mass as the distance between them triples, how would the gravitational
 attraction between them change?  
:
One way is to just assign some values to the masses and the distance
m1=10; m2=100; d=10
g = {{{(10*100)/10^2}}}
g = 1000/100
g = 10
"If the two objects each lose half of their mass as the distance between them triples, how would the gravitational attraction between them change? 
g = {{{(.5(10) * .5(100))/(3*10)^2}}} 
g = {{{(5*50)/(30^2)}}}
g = {{{250/900}}} reduces to {{{5/18}}}
then the relationship to the original g
{{{(5/18)/10}}} = {{{5/180}}} = {{{1/36}}}
:
We can say g is 1/36th