Question 1093456
If the object is propelled from a height of 12 feet with an initial velocity of 64 feet per second, it's [sic] height h is given by the equation h = -16t^2+64t+12. After how many seconds is the height 72 feet?
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h = -16t^2+64t+12 = 72
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-16t^2+64t+12 = 72
Solve for t.  What's the big deal?
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it's = it is