Question 1093430
Two cyclists leave towns 132mi  apart at the same time and travel toward each other. One cyclist travels 4 /mih [sic]  **** It's mi/hr ***  faster than the other. If they meet in 3  hours, what is the rate of each cyclist? 
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Speeds in opposite directions are added.
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Step 1, find the sum of the speeds.
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The difference is given, = 4 mi/hr.
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Call the speeds x & y
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x + y = sum
x - y = 4
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2x = sum + 4
etc.