Question 1093419
Use the dot product because,
{{{p*q=abs(p)abs(q)cos(theta)}}}
and given,
{{{abs(p)=sqrt(3^2+5^2)=sqrt(9+25)=sqrt(34)}}}
{{{abs(w)=sqrt(2^2+4^2)=sqrt(4+16)=sqrt(20)}}}
{{{p*q=3*2+5*4=6+20=26}}}
So substituting,
{{{26=sqrt(34)sqrt(20)cos(theta)}}}
{{{cos(theta)=26/sqrt(680)}}}
Solve for {{{theta}}}.