Question 1093348
(x-9)(x+3)(x+6)>(or equal) 0


(x-9)(x+3)(x+6)>=0


{{{(x-9)(x+3)(x+6)>=0}}}

Three critical x-values are  -6, -3, and 9.
The intervals on the real number line you want to check are (-infinity, -6], [-6, -3], [-3, 9], and [9, infinity).
Check any value within each interval to find if that interval works or not works.


<pre>
             (-infinity, -6]          [-6, -3]          [-3, 9]         [9, infinity)
signs        (-)(-)(-)                (-)(-)(+)         (-)(+)(+)       (+)(+)(+)
result sign   (-)                       (+)              (-)             (+)
              FALSE                      TRUE            FALSE           TRUE
</pre>
The solution set, of all the numbers that can make the equation true is
[-6,-3] U [9, infinity).



NOTE:  the form of the bracket for the interval notation, is important.  Square bracket INCLUDES the boundary value.  Curved bracket EXCLUDES the boundary value.