Question 1093363
y=ax+b/cx+d

You really mean,
y=(ax+b)/(cx+d)


{{{y=(ax+b)/(cx+d)}}}



First, question asked is about the INVERSE.
(assuming 'inverse relation')
{{{x=(ay+b)/(cy+d)}}}
{{{(cy+d)x=ay+b}}}
{{{cxy+dx=ay+b}}}
{{{cxy-ay=b-dx}}}
{{{y(cx-a)=b-dx}}}
{{{y=(b-dx)/(cx-a)}}}
{{{highlight_green(y=(-dx+b)/(cx-a))}}}


Horizontal asymptote, {{{y=-d/c}}}


Vertical asymptote, {{{x=a/c}}}