Question 1093262
sqrt(27x^3(y-2)*(cube root of (81x(y-2)^5)
= {{{sqrt(27x^3(y-2))*root(3,81x(y-2)^5)}}}
= {{{9x*sqrt(3x(y-2))*3(y-2)*root(3,3x(y-2)^2)}}}
= {{{27x*(y-2)sqrt(3x(y-2))*root(3,3x(y-2)^2)}}}
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Is that sufficient?
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= {{{27x(y-2)root(6,27x^3(y-2)^3)*root(6,9x^2(y-2)^4)}}}
= {{{27x(y-2)root(6,27x^3(y-2)^3*9x^2(y-2)^4))}}}
= {{{27x(y-2)root(6,243x^5(y-2)^7))}}}
= {{{27x(y-2)^2*root(6,243x^5(y-2)))}}}
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If you don't learn how to do that, life is gonna get hard for you.