Question 1093247
the half interval of a confidence interval is z*sqrt(p*(1-p))/n=0.01, the margin of error.
substitute
1.96*sqrt [(0.16*0.84)/n]=0.01
square both sides, multiply by n.
3.84*0.16*0.84=0.0001n=0.5161
divide by 0.0001
n=5161