Question 1093308
(3u^5v^4)^5(2u^4v^5)^-3
=(3u^5v^4)^5/(2u^4v^5)^3, by moving it to the denominator.
Raise each term in the numerator to the 5th power
243u^25*v^20/8u^12*v^15
can't reduce 243/8
u^25/u^12 is u^13, change the sign of the exponent when it crosses the fraction.
v^20/v^15=v^5, same thing
the result is (243u^13*v^5)/8