Question 1093291
By what number should (-3/2)to the power-3 be divided so that the quotient may be(4/27)to the power-2?
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(-3/2)^-3/n = (4/27)^-2
n = (-3/2)^-3/(4/27)^-2
Multiply NUM and DEN by (4/27)^2
n = (-3/2)^-3*(4/27)^2/1
Multiply NUM and DEN by (-3/2)^3
n = (4/27)^2/(-3/2)^3
n = (16/729)/(-27/8)
Invert the divisor and mutliply
n = (16/729)(-8/27)
n = -128/19683
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{{{n = -2^7/3^9}}}