Question 1093275
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Let S = the SUM of the two sons.
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The age of a man is twice the sum of the ages of his two sons,
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So the age of the man = 2S
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and five year ago his age...
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His age five years ago was 2S-5
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...was...
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equals
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thrice 
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3 times
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the sum of their ages.  
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S-10  [Why 10?  Because there are two sons and we must subtract
      [ 5 two times, once for each son. 

2S-5 = 3(S-10)

Solve that for S.  Then substitute what you get
for S in 2S to find the present age of the man.

Edwin</pre>