<PRE><B>Question 1093198</B>
A car goes on a short trip shown on this diagram. ( Diagram= a square with 4 legs labeled: A, B, C, and D).
 Each leg of the trip is 5km.
 The time from A to B was 6 min., from B to C took 12 min., C to D took 3 min., and finally, from D back to A took 9 min.
: 
speed = dist/time. 5km = 5000 m. change min to seconds (*60)
 a) what was the average speed along each leg of the trip?
AB: 5000/6(60) = 18.9 m/s
BC: 5000/12(60) = 6.9 m/s
CD: 5000/3(60) = 27.8 m/s
DA: 5000/9(60) = 9.3 m/s
:
 b) what was the average speed for the round trip?
4 * 5000 = 20000 m is the round trip
6+12+3+9 = 30 min is the total time
20000/30(60) = 11.1 m/s
 c) what was the average velocity for the whole trip?
He returned to the same point he started, velocity is 0
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