Question 1093236
If {{{x=log(4,7)}}} , then {{{4^x=7}}} .
taking logarithms base {{{e}}} on both sides of that equation,
we find the equivalent equation
{{{ln(4^x)=ln(7)}}} .
using the properties of logarithms, we get
{{{x*ln(4)=ln(7)}}} , and solving for {{{x}}} we get
{{{x=highlight(ln(7)/ln(4))}}} .