Question 1093227
Find the perimeter of the triangle with the vertices at 
(4, 2), (-5, 6), and (-7, -3).
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Label them.
A(4,2), B(-5,6), and C(-7,-3).
Find the 3 side lengths, AB, BC and AC
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{{{AB = sqrt(diffy^2 + diffx^2) = sqrt(4^2 + 9^2) = sqrt(97)}}}
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Find the other 2 sides the same way, then add them.