Question 1093219
{{{y = 4 -3x}}}.....eq.1
{{{3x + y = 5 }}}.....eq.2
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substitute {{{y}}} from eq.1 in eq.2

{{{3x + 4-3x = 5 }}}.....eq.2......solve for {{{x}}}

{{{cross(3x) + 4 -cross(3x) = 5 }}}

{{{ 4  = 5 }}}-> Since this equation is not true, we have an inconsistency.

So there are {{{no}}} solutions. The simple reason is the given equations represent two {{{parallel}}} lines that will never intersect. Since no intersections occur, no solutions exist.

{{{ graph( 600, 600, -10, 10, -10, 10, 4 -3x, 5 - 3x) }}}