Question 1093203
<br>To help follow the reasoning I use for my method of solving the problem, let's call the three numbers A, B, and C.<br>
For three consecutive odd integers, the middle number is equal to the average of the first and last numbers.
{{{B = (A+C)/2}}}<br>
That means that twice the middle number is equal to the sum of the first and last numbers.
{{{2B = A+C}}}<br>
So if three times the middle number is 11 more than the sum of the first and last, then the middle term must be 11.
{{{3B = (A+C)+11}}}
{{{2B+B = (A+C)+11}}}
{{{(A+C)+B = (A+C)+11}}}
{{{B = 11}}}<br>
And that makes the three integers 9, 11, and 13.