Question 1093092
as t increases, e^2.1t is increasing, since it is positive.
initial value is when t=0.  Then Q(t)=1300*e^0=1300.
after 1.5 seconds, Q(t)=1300e^3.15=30336.88.
2000=1300e^2.1t
1.538=e^2.1t
ln both sides
0.4307=2.1 t.
without rounding divide by 2.1
t=0.2051
{{{graph(300,300,-5,2.5,-10,50000,1300*e^(2.1x))}}}