Question 1092909
I'll take a stab at it
{{{ ( 3*tan(3theta ))^2 - 27 = 0 }}}
{{{ ( 3*tan( 3theta ))^2 = 27 }}}
{{{ 3^2*tan( 3theta )^2 = 27 }}}
{{{ tan( 3theta )^2 = 3 }}}
Take the square root of both sides
{{{ tan( 3theta ) = sqrt(3) }}}
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Since {{{ tan( pi/3 ) = sqrt(3) }}}
and, also
{{{ tan( pi + pi/3 ) = sqrt(3) }}}
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{{{ 3theta = pi/3 }}}
{{{ theta = pi/9 }}}
and also:
{{{ 3theta = 4*pi/3 }}}
{{{ theta = 4pi/9 }}}
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Get another opinion on this
( unless you know my solution is correct )