<PRE><B>Question 1092736</B>
N(t) = No * e^(r * t), where N(t) is population after time t, No is original population, r is growth rate, t is time
:
take natural log of both sides of =
:
ln(N/No) = r * t
:
r = ln(N/No) / t = ln(2,048,000/1000) / 60 = 0.1271
:
t = ln(N/No) / r
:
a) t = ln(2000/1000) /  0.1271 = 5.4536 hours
:
b) t = ln(4000/1000) /  0.1271 = 10.9071 hours
:
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