Question 1092700
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To solve this problem, group (MENTALLY) all the coins in sets containing 4 nickel and one dime each.


Each set (group) of coins then is worth  4*5+10 = 30 cents.


Hence, the number of such groups is  {{{390/30}}} = 13.


From this point, can you complete the solution on your own ?
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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/coins/Solving-coin-problems-mentally-by-grouping-without-using-equations.lesson>Solving coin problems mentally by grouping without using equations</A>

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