Question 1092699
Let {{{ d }}} = the one-way distance traveled
Let {{{ t }}} = time in hrs to get back
Equation for going there:
(1) {{{ d = 220*( t - 1 ) }}}
Equation to get back:
(2) {{{ d = 200t }}}
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Set (1) = (2)
{{{ 200t = 220*( t - 1 ) }}}
{{{ 200t = 220t - 220 }}}
{{{ 20t = 220 }}}
{{{ t = 11 }}}
and
{{{ t - 1 = 10 }}}
The trip there took 10 hrs
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check:
(2) {{{ d = 200*11 }}}
(2) {{{ d = 2200 }}} mi
and
(1) {{{ d = 220*( t - 1 ) }}}
(1) {{{ d = 220*10 }}}
(1) {{{ d = 2200 }}} mi
OK