Question 1092687
Solve for x:
10(x^2 - 49)/3x(x^2 - 4)(x + 1) = 0
Rewrite:
10/3x(x + 1)(x^2 - 49)(x^2 - 4) = 0
x(x + 1)(x^2 - 49)(x^2 - 4) = 0
x = 0; or x + 1 = 0; or x^2 - 49 = 0; or x^2 - 4 = 0
x = 0 or x = -1 or x^2 - 49 = 0 or x^2 - 4 = 0
x = 0 or x = -1 or (x - 7)(x + 7) = 0 or x^2 - 4 = 0
x = 0 or x = -1 or x - 7 = 0 or x + 7 = 0 or x^2 - 4 = 0
x = 0 or x = -1 or x = 7 or x = -7 or x^2 - 4 = 0
x = 0 or x = -1 or x = 7 or x = -7 or x^2 - 4 = 0
x = 0 or x = -1 or x = 7 or x = -7 or (x - 2)(x + 2) = 0
x = 0 or x = -1 or x = 7 or x = -7 or x - 2 = 0 or x + 2 = 0
x = 0 or x = -1 or x = 7 or x = -7 or x = 2 or x = -2